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kotegsom [21]
4 years ago
14

A 200 Hz tuning fork is sounded at the same time as a guitar string and a beat frequency of 4 Hz is heard. Which of the followin

g could be the natural frequency of the guitar string? (a) 192 Hz, (b) 196 Hz, (c) 200 Hz, (d) 208 Hz, (e) 800 Hz.
Physics
1 answer:
leva [86]4 years ago
7 0

Explanation:

It is given that,

Frequency of the tuning fork, f₁ = 200 Hz

Beat frequency, f_b=4\ Hz

The difference of frequencies is called the beat frequency of the tuning fork. It is given by :

|f_1-f_2|=4

200-f_2=\pm 4

f_2=196\ Hz

or

f_2=200\ Hz

So, the correct option is (b) "196 hertz". Hence, this is the required solution.

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An electron in an electron gun is accelerated from rest by a potential of 25 kV applied over a distance of 1 cm.
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Answer:

9.38\times 10^7 m/s

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Which describes the characteristics of a liquid?
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The distance between two objects is increased by three times the oringinal distance. How will this change the force of attractio
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8 0
3 years ago
Calculate the force between two objects that have masses of 70 kilograms and 2,000 kilograms separated by a distance of 1 meter.
Makovka662 [10]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Gravitational Force between given objects will be ~

  • 9.34 \times  {10}^{ - 6}  \:  \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where ~

  • F = gravitational force

  • m_1 = mass of 1st object = 70 kg

  • m_2 = mass of 2nd object = 2000 kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 1 m

Let's calculate the force ~

  • F =  \dfrac{6.674 \times 10 {}^{ - 11} \times 70 \times 2000 }{1 {}^{2} }

  • F =6.674 \times 7 \times 2 \times 10 { }^{ - 11} \times 10 {}^{4}

  • 93.436 \times 10 {}^{ - 7}

  • 9.3436  \times 10 {}^{ - 6} \:  \:  newtons
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3 years ago
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