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kotegsom [21]
4 years ago
14

A 200 Hz tuning fork is sounded at the same time as a guitar string and a beat frequency of 4 Hz is heard. Which of the followin

g could be the natural frequency of the guitar string? (a) 192 Hz, (b) 196 Hz, (c) 200 Hz, (d) 208 Hz, (e) 800 Hz.
Physics
1 answer:
leva [86]4 years ago
7 0

Explanation:

It is given that,

Frequency of the tuning fork, f₁ = 200 Hz

Beat frequency, f_b=4\ Hz

The difference of frequencies is called the beat frequency of the tuning fork. It is given by :

|f_1-f_2|=4

200-f_2=\pm 4

f_2=196\ Hz

or

f_2=200\ Hz

So, the correct option is (b) "196 hertz". Hence, this is the required solution.

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a = m V^2 / R = m ω^2 R   where R is the radius vector of the velocity - note that the Radius vector is directed from the center of motion to the object and for circular motion would be constant in magnitude but not  in direction

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