Answer:
m1=914.9kg
m2=604.9kg
m3=864.75kg
Explanation
I think we are suppose to find the mass of the crate.
The effective force that moves the body in positive x direction is 3615N
ΣFx = Σma
Then Fx=3615N
Then the masses be m1, m2 and m3
Then,
ΣF = Σ(ma)
3615=(m1+m2+m3)a
Given that a=1.516
The masses are
m1+m2+m3=, 2384.56. Equation 1
Between mass 1 and mass 2 is, F12=1387.
The effective force that pull mass 1 is 1387.
F12=m1 ×a
Therefore,
m1=F12/a
m1=1387/1.516
m1=914.9kg.
The effective force that pulls crate 1 and crate 2 is F23
F23=(m1+m2)a
Therefore
2304=(m1+m2)a
Therefore, since a=1.516
m1+m2=2304/1.516
m1+m2=1519.8kg
Since m1=914.9kg
So, m2=1519.8-m1
m2=1519.8-914.9
m2=604.9kg
Also from equation 1
m1+m2+m3=2384.56
Since m1=914.9kg and m2=604.9kg
Then, m3=2384.56-604.9-914.9
m3=864.75kg
Answer: 80.384 cubic cm /min
Explanation:
Let V denote the volume and r denotes the radius of the spherical snowball .
Given : 
We know that the volume of a sphere is given by :-
Differentiating on the both sides w.r.t. t (time) ,w e get
When r= 8 cm
Hence, the volume of the snowball decreasing at the rate of 80.384 cubic cm /min.
Air resistance is a force that slows down objects moving through the air. ... Objects are affected by gravity the same, but air resistance can affect the speed of an object's descent. An object with more surface area will have more air resistance.
Answer:
12 m/s
Explanation:
Given data
Mass m= 1500kg
intitial velocity u= 20m/s
force F= 6000N
time t= 2 seconds
Required
The final velocity v
From
Ft= mΔv
Ft= m(u-v)
substitute
6000*2= 1500(20-v)
solve for v
12000= 30000- 1500v
collect like terms
12000-30000= -1500v
-18000= -1500v
divide both sides by -1500v
v= 18000/1500
v=12 m/s
Hence the velccity is 12 m/s
Answer:
synthesis is correct answer.
