Find the v first by using 3.14x0.22x2.16 div. 41g
Answer: 
Explanation:
Given
Initial angular velocity is 
rate of reduction 
after 17 revolution i.e. 
using 
Insert the values
Answer:
5J/mol
Explanation:
H-H eclipsed = Torsional strain = 4.0 kJ/mol
H-CH3 eclipsed = Mostly torsional strain = 6.0 kJ/mol
CH3-CH3 eclipsed =Torsional and steric strain = 11.0 kJ/mol
CH3-CH3 gauche = Steric strain = 3.8 kJ/mol
You know each H-H eclipsed is 4 kJ/mol (8 kJ/mol total) and the reported barrier is 13 kJ/mol. Therefore the H-I eclipsed interaction must be 5 kJ/mol, (13-8 = 5).
We are given the following:
thickness, T = 0.155 mm
charge-carrier density, n = 1.05 x 10^25 / m3
current, I = 2.67 A
voltage, V = 4.89 mV
We are asked to get the magnetic strength, B
To solve this, we use the Hall Effect formula:
V = - IB / neT
where e is the charge of an electron which is e = 1.60 x 10^-19 and B is the magnetic field
Rearranging the formula
B = -V n e T / I
Substituting the given values
B = - (4.89 x 10^-3 V) (1.05 x 10^25 / m3) (0.155 x 10^-3 m) / 2.67 A
B = -2.98 x 10^18 Teslas
Answer:
Yes because of the temputer
Explanation:
