Answer:
Angular spread, 
Explanation:
It is given that,
Wavelength of the light, 
Diameter of the telescope, D = 5.08 m
The minimum angular spread is given by :



So, the minimum angular spread of the beam is
. Hence, this is the required solution.
the second option is your answer to what a liquid is
M = 20.0kg, the mass of the block.
c = 1700 J/(kg-°C), the specific heat
ΔT = 25 - 15 = 10 °C = 10 K, the change in temperature.
The change in thermal energy is

Answer: 340 kJ (or 340,000 J)
V^2 = 700J/0.5*35kg
V = square root of 40
v = 6.324 m/s