Answer:$ 43.20
Step-by-step explanation: I think this is right I just worked it out
The answer is 13/15.
2/5 = 12/30
2/3 = 20/30
12/30 + 20/30 - 6/30 = 32/30 - 6/30 = 26/30 = 13/15.
The rule for the reflection is (x,y,z) → (-x,y,z) so P' = (1, 2, 0) for example.
<span>Then the rule is (x,y,z) → (x + 2, y + 4, z - 3) so P'' = (3, 6, -3) </span>
Answer:

Step-by-step explanation:
<u>Trigonometric Identities</u>
If the trigonometric function value of an angle is given, we can find the rest of the trigonometric values of the angle by using one or more of the fundamental identities.
To solve this problem, we need to use the following identities:


Since we are given:

And the angle is in the first quadrant, calculate the cotangent:



The tangent is:

Rationalizing the denominator:


Answer:
<em>it's an isosceles triangle, because two sides are the same length, and thus two angles are also the same.</em>
<em> * mark as brainliest please../;(</em>
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Step-by-step explanation: