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3 years ago

Which of the following carbon-based molecules stores information

Chemistry

1 answer:

Eduardwww [97]3 years ago

8 0

The following carbon-based molecules store information are found in living things.

All organism are made of 4 type of carbon-based= carbon hydrate, lipids, proteins, and nuclear acid

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The percentage of the earth’s atmosphere today is the same as it was in the earths early atmosphere. Suggest why.

jek_recluse [69]

Explanation:

Once the earth's atmosphere was formed it really hasn't changed since, this is due to many reasons. Whatever created the earth's atmosphere (we don't know) has long disappeared, because of this the atmosphere cannot change, as there is nothing on earth that can change it (that we know of at least). Hopefully this helps.

7 0

3 years ago

What mass of salt would you need to add to 1.00kg of water to achieve a freezing point of -5 degrees C

Serga [27]

Answer:

The type of salt to be added to the water is not known from the question but no worries, I will try to give you the step by step procedure to answer any type of question similar to this.

To answer this question, we should know some facts.

1. the molar freezing point depression constant of water (Kf) = 1.86 K kg/mol

2. the molar mass of the salt if NaCl = 58.5 g/mol ; KCl = 74.5 g/mol

3. since the salt can dissociate if NaCl or KCl into two ions, the Van't Hoff factor ( i )= 2

Note that: the change in freezing point, molarity, deepression constant and van't Hoff factor are related by this formula;

ΔTf = i Kf m

So lets take NaCl as the salt:

Molar mass = 58.5 g/mol

Van't Hoff factor = 2

1. calculate the number of moles

So we can calculate the molarity of the salt NaCl from the formula;

m = ΔTf / i Kf

m = 5 / 2 * 1.86

m = 5 / 3.72

m = 1.344 mol/kg

2. calculate the number of moles of the salt required

Next is to multiply the molarity by the mass of water. Density of water = 1kg/L

number of moles = 1.344 mol/kg * 1 Kg/L * 1 kg water

number of moles = 1.344 moles.

3. calculate the mass of the salt.

numner of moles = mass / molar mass

mass = number of moles * molar mass

mass = 1.344 * 58.5

mass = 78.624 g of NaCl salt.

You can follow these steps to solve for the type of salt you are given in the question.

6 0

4 years ago

What do we call living things that share characteristics including processes that make life possible?

Dafna11 [192]

Answer:
Organisms

Step-by-step explanation:

Properties of Life. All living organisms share several key characteristics or functions: order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.

6 0

3 years ago

When Coach Kwan notices that a player is getting tired, she takes out the tired player and substitutes a fresh player. Which typ

kotegsom [21]

Answer: Single replacement Reaction

Explanation:

A replacement reaction is a chemical reaction in which an element replaces another element in a compound especially when it is more reactive than the former. There are two types of replacement reaction, the single and double replacement reaction.

In the former, one element which is usually more reactive than the other replaces it . For example in the single replacement, a more reactive metal replaces a less reactive metal and also a more reactive non metal can replace a less reactive non metal.

A + BC → B + AC

looking at the equation aove, you can see that B replaces A

Also In double replacement, the elements in the both reacting compounds are replaced or exchanged to form new compounds as can be illustrated in the equation

AB + CD —— AC + BD

In the case of Coach Kwan, she follows the Single replacement model as she substitutes a less active and tired player with an active one.

3 0

3 years ago

A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t

andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

$\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)$