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stealth61 [152]
3 years ago
14

A heat lamp produces____ light.

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

infrared light

Explanation:

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Which is the following statement that describe an organism that produce offspring
Natalka [10]
Im not sure what the answer is unless you put the options up for the multiple choice
8 0
3 years ago
The solubility of acetanilide in hot water (5.5 g/100 ml at 100∘C) is not very great, and its solubility in cold water (0.53 g/
Olin [163]

Answer:

89.4%

Explanation:

Initially, there is 5.0 of the acetanilide in 100 mL of water, then the solution is chilled at 0ºC. The solubility represents the amount that the solvent (water) can dissolve of the solute (acetanilide). So, at 0ºC, 100 mL of water can dissolve till 0.53 g of the compound, the rest will precipitate and will be recovered.

So, the mass that is recovered is 5.0 - 0.53 = 4.47 g

The percent recovery is:

(4.47/5)x100% = 89.4%

8 0
4 years ago
A heat pump is used to heat a house in the winter and to cool it in the summer. During the winter, the outside air serves as a l
elixir [45]

Answer:

T_{C} = -4.2°C

T_{H} = 49.4°C

Explanation:

A Carnot cycle is known as an ideal cycle in thermodynamic. Therefore, in theory, we have:

|\frac{Q_{C} }{Q_{H} }| = \frac{T_{C} }{T_{H} }

Similarly,

|Q_{H}| = |Q_{C}| + |W_{S}|

During winter, the value of |T_{H}| = 20°C = 273.15 + 20 = 293.15 K and |W_{S}| = 1.5 kW. Therefore,

|Q_{H}| = 0.75(T_{H} -  T_{C})

Similarly,

|\frac{W_{S} }{Q_{H} }| = 1 - \frac{T_{C} }{T_{H} }

1.5/0.75*(293.15-T_{C}) = 1 - (T_{C}/293.15

Further simplification,

T_{C} = -4.2°C

During summer, T_{C} = 25°C = 273.15+25 = 298.15 K, and |W_{S}| = 1.5 kW. Therefore,

|Q_{C}| = 0.75(T_{H} -  T_{C})

Similarly,

|\frac{W_{S} }{Q_{C} }| = \frac{T_{H} }{T_{C} } - 1

1.5/0.75*(T_{H} - 298.15) = (T_{H}/298.15

Further simplification,

T_{H} = 49.4°C

4 0
4 years ago
Negative radical in the periodic table<br>​
AVprozaik [17]

Answer:

Negative Radicals ---→

1).Flouride =  F⁻

2). Chloride = Cl⁻

3) Bromide = Br⁻

4) Iodide = I⁻

5) Sulphate = SO₄²⁻

6) Oxide = O²⁻

7) Nitride = N³⁻

8) Sulphur = S²⁻

9) Carbide = C⁴⁻

10) Hydroxide = OH⁻

11) Nitrate = NO₃⁻

12) Carbonate = CO²⁻

13) Hydrogen Carbonate = HCO₃⁻

14) Sulphate = SO₄²⁻

15).Sulphite = SO₃³⁻

16) Nitrate = NO₃⁻

17)Nitrite = NO₂⁻

18) Hydrogen Sulphite = HSO₃⁻

19) Hydrogen Sulphate = HSO₄⁻

20) Chromate = CrO₄²⁻

There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.

Hope it helps,

Please mark me as the brainliest

Thank you

7 0
3 years ago
Which of the following is not the same as 8,540 centigrams?
Dahasolnce [82]
8.54 Probably a little too late but, hey better late than never lol
8 0
3 years ago
Read 2 more answers
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