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Kipish [7]
3 years ago
15

Who wants to do my math work for me for $20 for a month?

Mathematics
2 answers:
TEA [102]3 years ago
8 0

Answer:

what type of math is it?

nadezda [96]3 years ago
3 0

Answer:

i will do your math for a brainliest for every question i answer and for no pay  

Step-by-step explanation:

You might be interested in
Help me please its math
Reptile [31]
D=10
Explanations: 2d-5=3d- 15
2d- 3d =-15+5
D=10
6 0
2 years ago
How many nanoseconds does it take for a computer to perform one calculation if it performs calculations per second?
igor_vitrenko [27]

I believe the correct question is:

6.7*10^7 calc/sec?

 

So:

1/(6.7 x 10^7) = seconds per calculation

1/(6.7 x 10^7) = 100/(6.7 x 10^9) = 14.9 x 10^-9 seconds per calculation = 14.9 ns

Which is approximately 15 ns

 

Answer:

15 ns

7 0
3 years ago
If the angles are in the ratio 2:7:11 then find the angles
german

Answer: 180 is the sum of the tringles


Step-by-step explanation:

2x+7x+11x=180

20x=180

x=9

Now you should put the the value of x to get the angles

2x=2x9=18

7x=7x9=63

11x=11x9=99

Now to double check add all of them together

99+18+63=180

Hoped I helped!


5 0
3 years ago
(PLEASE HELP PLEASE!! IM GOING TO FAIL) PLEASE HELP ME WITH THESE QUESTIONS!! NOT JUST FOR ME FOR BRAIN! WHO WILL ANSWER FIRST?!
Lina20 [59]
1. A
2. should be 42?
3.???
4.27 apples left
5.B 1/4
7 0
3 years ago
Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat
Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

T=60+40e^{kt}

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

T=60+40e^{kt}

at T = 90°C and  t = 3 minutes

90=60+40e^{k(3)}

30=40e^{3k}

or

e^{3k}=\frac{3}{4}

taking the natural log both sides, we get

3k = \ln(\frac{3}{4})

or

3k = -0.2876

or

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

65=60+40e^{( -0.09589)t}

or

5=40e^{( -0.09589)t}

or

e^{( -0.09589)t}=\frac{5}{40}

or

e^{( -0.09589)t}=0.125

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

or

( -0.09589)t = -2.0794

or

t = 21.68 minutes ≈ 21.7 minutes

6 0
3 years ago
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