Answer:
steps below
Step-by-step explanation:
f(x) = x⁷ – 6x⁶ + 8x⁵
f'(x) = 7x⁶ - 36x⁵ + 40x⁴
= x⁴ (7x² - 36x + 40) ... (1)
Critical point (x,y): x = 0 , x = (36 ± √(-36)²-4*7*40) / (2*7) = (18±2√11) / 7
x = 0 or x = 3.5 or x = 1.6
plug into (1): y = 0 , y = -394.3 , y = 10.1
extreme : <u>maximum (1.6 , 10.1)</u> <u>minimum (3.5 , -394.3)</u> ... turning points
x⁷ – 6x⁶ + 8x⁵ = x⁵ (x² - 6x + 8) = x⁵ (x-2) (x-4) =0
<u>real zeros: x = 0, x=2, x=4</u>
Answer:
The number of tables were used that day at lunch is 23 tables.
Step-by-step explanation:
Given as :
The total number of students in the Polk school = 203
On one day the number of students absent = 19
So, The number of student present on that day = Total student - absent students
I.e The number of student present on that day = 203 - 19 = 184
The number of students sit on each table = 8
Let The number of tables were used that day at lunch = n
<u>So, According to question</u>
The number of tables were used that day at lunch = 
I.e n = 
∴ n = 23 tables
So, The number of tables were used that day at lunch = n = 23 tables
Hence, The number of tables were used that day at lunch is 23 tables. Answer
Answer:
0
Step-by-step explanation:
hope this helps :)
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