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2 years ago

Please me the shapes are confusing me please help quickly

Mathematics

1 answer:

nikdorinn [45]2 years ago

8 0

Can you show the full screen ?

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Help me plz branniest to whoever right

storchak [24]

(3x+7)+(4x+9)=-58
first add like terms
7x+16=-58
subtract 16 from both sides
-7x=-74
divide -7 from both sides
x=10.6
its 10.6 units long

7 0

3 years ago

Does the point (4, 0) satisfy the equation y = x2?

andre [41]

Y=x^2
substitute the values into the original equation
0=4^2
0=16
No it does not satisfy the equation because 0 does not equal to 16

8 0

2 years ago

At Walmart, apples cost $0.50 each, and grapefruits cost $2 each. You want to spend exactly $15.

Papessa [141]

Define the variables: a is the number of apples I can buy g is the number of grapefruits I can buy.

Write the equation: 15 = 0.50a + 2g

6 0

3 years ago

Pls answer these questions

Juli2301 [7.4K]

Answer:

the images not loading so can you please upload it again

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I need help please.

makkiz [27]

Answer:

see explanation

Step-by-step explanation:

Using the rules of radicals/ exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

$a^{\frac{m}{n} }$ ⇔ $\sqrt[n]{a^{m} }$

Simplifying each term

7 $\sqrt{x^{3} }$ = 7 $x^{\frac{3}{2} }$

x $\sqrt{9x}$

= x × $\sqrt{9}$ × $\sqrt{x}$

= x × 3 × $x^{\frac{1}{2} }$

= 3 × $x^{(1+\frac{1}{2}) }$

= 3 $x^{\frac{3}{2} }$

Subtracting the 2 simplified like terms, that is

7 $x^{\frac{3}{2} }$ - 3 $x^{\frac{3}{2} }$

= 4 $x^{\frac{3}{2} }$ ← return to radical form

= 4 $\sqrt{x^{3} }$

8 0

2 years ago

Please me the shapes are confusing me please help quickly ​

Please me the shapes are confusing me please help quickly