The molar mass is calculated by looking up the relative atomic mass values on a periodic table. The relative atomic mass is a value without units that is calculated on a Carbon-12 scale.
By looking at the periodic table (values will be to 3 significant figures [<em>2</em><em> for hydrogen though]</em>):
Molar mass (M) of 1 mole of Carbon = 12.0 g/mol
Molar mass (M) of 1 mole of Hydrogen = 1.0 g/mol
Molar mass (M) of 1 mole of Oxygen = 16.0 g/mol
So the molar mass is essentially the relative atomic mass (RAM), but molar mass has a unit, but RAM doesn't (it is a ratio).
Given the formula is C6H12O6 (without putting the numbers as subscripts), we can calculate as follows:
M (C6H12O6) = (6 x 12.0) + (12 x 1.0) + (6 x 16.0)
= 72.0 + 12.0 + 96.0
= 180.0 g/mol
Hope it's right :D
Answer : The molecular formula of benzoyl peroxide is 
Explanation :
Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.
Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :

As we are given that the molar mass of compound is, 0.242 kg/mol.
Molecular mass = 0.242 kg/mol = 242 g/mol (1 kg = 1000 g)
The empirical mass of
= 7(12) + 5(1) + 2(16) = 121 g/eq



Molecular formula =
=
= 
Thus, the molecular formula of benzoyl peroxide is 
Answer:
The pH of the solution is 1.38.
Explanation:
Mass of HCl = 614 mg = 0.614 g
Moles of HCl = 
Concentration of HCl :

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.
![[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M](https://tex.z-dn.net/?f=%5BHCl%5D%3D%5Cfrac%7B0.01682%20mol%7D%7B0.4%20L%7D%3D0.04205%20M)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.
Then 0.04205 mol/L of HCl will give:
of hydronium ions.
![[H_3O^+]=0.04205 M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D0.04205%20M)
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pH=-\log [0.04205 M]=1.38](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5B0.04205%20M%5D%3D1.38%20)
The pH of the solution is 1.38.
Answer:
um la cookie on a bar was a waste of color with climax of gdhel of
Answer:
Average of measurements = 20.97 cm
Explanation:
Given data:
Three measurements of pete's = 20.9 cm, 21.0 cm, 21.0 cm.
Average value of measurements = ?
Formula:
Average of measurements = sum of all measurements / Total number of measurements
Solution:
Average of measurements = 20.9 cm + 21.0 cm + 21.0 cm. / 3
Average of measurements = 62.9 cm / 3
Average of measurements = 20.97 cm