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givi [52]
3 years ago
12

A rigid container (volume cannot change) is filled with carbon dioxide gas at room temperature. The container is then placed in

a sub-zero freezer with temperatures around -40 °C. The amount of gas in the container is fixed and cannot change. A pressure sensor and a thermometer are mounted inside the container to collect data.
What happens to the temperature of the gas inside the container?
Chemistry
1 answer:
Sedbober [7]3 years ago
3 0

The reduction in the temperature leads to an automatic decrease in the pressure of the gas inside the he container. This is due to the decreased number of collisions per unit area of the container walls. Pressure law states that at constant volume, the pressure of a fixed mass of a gas is directly proportional to the absolute temperature.

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I need help assapppp
DedPeter [7]

Answer:

Lithium has 3 protons, 4 neutrons, 3 electrons, and its mass is 6.941 u

4 0
3 years ago
Which pair are classified as chemical substances? Pick two.
maria [59]
Elements and compounds. This is because in solutions and mixtures the substances are not bonded to each other or pure, you can separate and purify substances in solutions and mixtures (via techniques such as distillation, filtering) but you cannot separate compounds as they are bonded together.
8 0
4 years ago
What is the atomic number of the as yet undiscovered element in which the 8s and 8p electron energy levels?
Andreyy89

The atomic number of the undiscovered element is 168

Element 118 will have just filled its 7p orbitals. therefore the predicted element to fill completely up to its 8 p orbital would have to filled a whole set of s, p, d, f and g orbitals

That's another 2 + 6 + 10 +14 + 18 = 50 electrons

To determine the total number of quantum numbers we have to find

Nml × Nms

we have Nml × Nms = ( 2 + 1 ) × 2

8s + 8P + 7d + 6f + 5g = 2 + 6 + 10 + 14 + 18 = 50

The element right below should be

Z = 118 + 50

   = 168

Hence the atomic number of the undiscovered element is 168

Learn more about the atomic number on

brainly.com/question/14514242

#SPJ4

4 0
1 year ago
Compare which element would have larger first ionization energy: an alkali metal in Period 2 or an alkali metal in Period 4?
maria [59]

Answer:

An alkali metal present in period 2 have larger first ionization energy.

Explanation:

Ionization energy:

The amount of energy required to remove the electron from the atom is called ionization energy.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.  Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.

6 0
3 years ago
BRAINLIEST ANSWER.... How many bonding and nonbonding electrons are on the nitrogen atom in NO2?
ioda

The answer would be C there would be 6 nonbonding electrons and 2 bonding electrons.

5 0
3 years ago
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