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Yanka [14]
3 years ago
14

Aluminum has a density of 2.70 g/m. Calculate the mass (in grams) of a piece of aluminum having a volume of 382 mL

Chemistry
1 answer:
Natalka [10]3 years ago
8 0

The aluminum has a mass of 1031.4 grams.

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The first step in the scientific methods is ask a question
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A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the
yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X  1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of  H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

For a detailed study of the empirical formula refer given link brainly.com/question/13058832.

#SPJ1.

5 0
1 year ago
The activation energy of a chemical reaction is the energy that
Svetlanka [38]

Explanation:

The activation energy of a chemical reaction is the amount of energy that must be added to go from the energy level of the reactants to the energy level of transition state.

3 0
3 years ago
2074 Set B Q.No. 1 What mass of nitrogen will be requires
timurjin [86]

140 g of nitrogen (N₂)

Explanation:

We have the following chemical equation:

N₂ + 3 H₂ -- > 2 NH₃

Now, to find the number of moles of ammonia we use the Avogadro's number:

if        1 mole of ammonia contains 6.022 × 10²³ molecules

then   X moles of ammonia contains 6.022 × 10²⁴ molecules

X = (1 × 6.022 × 10²⁴) / 6.022 × 10²³

X = 10 moles of ammonia

Taking in account the chemical reaction we devise the following reasoning:

If        1 mole of nitrogen produces 2 moles of ammonia

then  Y moles of nitrogen produces 10 moles of ammonia

Y = (1 × 10) / 2

Y = 5 moles of nitrogen

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of nitrogen (N₂) = 5 × 28 = 140 g

Learn more about:

Avogadro's number

brainly.com/question/13772315

#learnwithBrainly

7 0
3 years ago
I’m screwed omg i totally forgot I have school today and forgot to do this someone help me rq I’ll brainlist plslsls be awake ju
zlopas [31]

Answer:

Zn + O2 = ZnO

Mg + O2 = MgO

Cu + O2 = CuO

Al + O2 = Al2O3

Explanation:

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