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OleMash [197]
3 years ago
5

What is the effect on pollution when cool air becomes trapped under warm air?

Chemistry
2 answers:
Paha777 [63]3 years ago
6 0

Answer:

more pollutants accumulate. Hope I helped! c: C:

Explanation:

sergejj [24]3 years ago
3 0
More pollutants accumulate
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Additional solute is added to a saturated solution of a solid and a liquid after being heated above room temperature. Once no mo
PSYCHO15rus [73]

Answer:

After the solution is heated, but before additional solute is added

Explanation:

An unsaturated solution is a solution that contains less solute than it can normally hold at a given temperature. Hence an unsaturated solution can still dissolve more solute.

When the solution is heated, the saturated cold solution becomes an unsaturated hot solution which is capable of dissolving more solute at this point.

Once more solute is dissolved, the solution becomes saturated again just before it begins to cool since no more solute dissolves in the solution at some point before cooling and addition of seed crystals.

4 0
3 years ago
You have 0.5 l of air at 203 k in an expandable container at constant pressure. you heat the container to 273 k. what is the new
Leviafan [203]
0.593 L. V1/T1 = V2/T2
5 0
3 years ago
A solution of H 2 SO 4 ( aq ) H2SO4(aq) with a molal concentration of 8.01 m 8.01 m has a density of 1.354 g / mL . 1.354 g/mL.
anzhelika [568]

Answer:

[H₂SO₄] = 6.07 M

Explanation:

Analyse the data given

8.01 m → 8.01 moles of solute in 1kg of solvent.

1.354 g/mL → Solution density

We convert the moles of solute to mass → 8.01 mol . 98g /1mol = 785.4 g

Mass of solvent = 1kg = 1000 g

Mass of solution = 1000g + 785.4 g = 1785.4 g

We apply density to determine the volume of solution

Density = Mass / volume → Volume = mass / density

1785.4 g / 1.354 g/mL = 1318.6 mL

We need this volume in L, in order to reach molarity:

1318.6 mL . 1L / 1000mL = 1.3186 L ≅ 1.32L

Molarity (mol/L) → 8.01 mol / 1.32L = 6.07M

4 0
3 years ago
Read 2 more answers
What is the density of and object that is 100 grams and has a volume of 5 cubic centimeters?
lesya [120]

Explanation:

Density of object = gram/volume

= 100 g/ 5 cm³

= 20 g/cm³

5 0
3 years ago
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What will be the products in the reaction: AI + BaCI2
Anvisha [2.4K]
——>Ba+AlCl2
—->3Ba+2AlCl3 to balance the equation
8 0
3 years ago
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