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Vikentia [17]
3 years ago
13

Express x in terms of a and b: b−7x=a−b

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0
B - 7x = a - b
Subtract b from both sides.

-7x = a - 2b
Divide both sides by -7.

x = \frac{-a + 2b}{7}
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Q. Which graph represents the solutions to the inequality |2x − 4| less than or equal to 14?
alina1380 [7]
The answer should actually be option B)

hope this helped and please vote me brainiest

7 0
3 years ago
What is the equation of the line shown below?
miskamm [114]

Answer:

y= 1x - 1

Step-by-step explanation:

Slope-intercept form: y=mx + b

(-4,-5) (5,4)

m= (y2 - y1)/(x2 - x1) = (4+5)/(5+4)=1

4=1(5)+b

4=5 + b    4-5=b    b= -1

y= 1x - 1

7 0
3 years ago
2/3 gas tank cuts 3 lawns how many does 1 gas tank cut
postnew [5]
(2/3) / 3 = 1/x...2/3 to 3 lawns = 1 to x lawns
cross multiply
(2/3)(x) = (3)(1)
2/3x = 3
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8 0
3 years ago
Find the mean of the following<br> data set.<br> 1,1,2,4,6,7,7,8,9,10,12,13,17,17,18
lisabon 2012 [21]

Answer:

8.8

Step-by-step explanation:

Add all numbers together to get 132

All number of numbers together to get 15

Divide the sum of all numbers by the number of numbers:

132/15

8.8

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6 0
2 years ago
Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
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