Answer:
The temperature drop is 61.1 °C
The final specific volume of the refrigerant is 1.236 m^3/kg
Explanation:
Initial pressure of refrigerant = 800 kPa = 800/100 = 8 bar
Final pressure of refrigerant = 140 kPa = 140/100 = 1.4 bar
From steam table
At 8 bar, initial saturated temperature is 170.4 °C
At 1.4 bar, final saturated temperature is 109.3 °C
Temperature drop = initial saturated temperature - final saturated temperature = 170.4 - 109.3 = 61.1 °C
Also, from steam table
At 1.4 bar, specific volume is 1.236 m^3/kg
Final specific volume of the refrigerant is 1.236 m^3/kg
