PLEASE HURRY TIMED TEST
2 answers:
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The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Calculate the equivalent capacitance of the three series capacitors in Figure 12-1
a) 0.01 μF
b) 0.58 μF
c) 0.060 μF
d) 0.8 μF
Answer:
The equivalent capacitance of the three series capacitors in Figure 12-1 is 0.060 μF
Therefore, the correct option is (c)
Explanation:
Please refer to the attached Figure 12-1 where three capacitors are connected in series.
We are asked to find out the equivalent capacitance of this circuit.
Recall that the equivalent capacitance in series is given by
Where C₁, C₂, and C₃ are the individual capacitance connected in series.
C₁ = 0.1 μF
C₂ = 0.22 μF
C₃ = 0.47 μF
So the equivalent capacitance is
Rounding off yields
The equivalent capacitance of the three series capacitors in Figure 12-1 is 0.060 μF
Therefore, the correct option is (c)
Answer:
The heater load =35 KJ/kg
Explanation:
Given that
At initial condition
Temperature= 15°C
RH=80%
At final condition
Temperature= 50°C
We know that in sensible heating process humidity ratio remain constant.
Now from chart
At temperature= 15°C and RH=80%
At temperature= 50°C
The heater load = 73 - 38 KJ/kg
The heater load =35 KJ/kg