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goldenfox [79]
3 years ago
15

What major advancement in machine tools occurred in the 1970s and what benefits did it provide? describe in your own words.

Engineering
2 answers:
mixer [17]3 years ago
4 0

Answer:

I'm just a seventh grader

kolbaska11 [484]3 years ago
4 0

Answer:

here's an essay I wrote one this topic

Explanation:

The early 1970s saw price and wage freezes and high unemployment. The oil crisis of 1973 and 1979 served to help slow an already snail-paced economy, and by 1979, the U.S. was experiencing the worst inflation in 33 years.

A growing world market was not helping the economic transition as traditionally strong big businesses like automotive and steel lost market shares to Europe and Japan. At the beginning of the decade, the government bailed out Lockheed Martin with $250 million worth of loan guarantees. Later it did the same for Chrysler—to the tune of $1 billion.

Obviously, the old ways of doing business were failing. The seeds of concern about more efficient operations, more flexibility, and higher quality were taking root in this decade for the eventual growth of a new paradigm in manufacturing that would flourish in the 80s. As NCs and DNCs gained recognition and popularity, the benefits of faster, more accurate cutting began to make demands on traditional tooling, controls, inspection, and other facets of the manufacturing process. This led to the development of many new companies who were ready to meet the challenges of a transitioning decade and make the products that would fulfill the needs of a new world of manufacturing.

As manufacturers looked for inexpensive solutions to their problems, those in the machine tool industry responded with new, lower-cost technologies. GE Fanuc Automation for one developed its Mark Century 550 Series in 1970. The highly-reliable control system was marketed as a complex, low-cost NC and became popular in the worldwide market. It introduced new features like lathe canned cycles, spindle speed monitor, battery backed tool offset, RAM memory, and cutter compensation.

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ra1l [238]

Answer:

True

Explanation:

Always see a professional if you have any issues that is not in your scope of practice

7 0
3 years ago
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A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 30.00 a
IrinaVladis [17]

Answer:

The original length of the specimen l_{o} = 104.7 mm

Explanation:

Original diameter d_{o} = 30 mm

Final diameter d_{1} = 30.04 mm

Change in diameter Δd = 0.04 mm

Final length l_{1} = 105.20 mm

Elastic modulus E = 65.5 G pa = 65.5 × 10^{3} M pa

Shear modulus G = 25.4 G pa = 25.4 × 10^{3} M pa

We know that the relation between the shear modulus & elastic modulus is given by

G = \frac{E}{2(1 + \mu)}

25.5 = \frac{65.5}{2 (1 + \mu)}

\mu = 0.28

This is the value of possion's ratio.

We know that the possion's ratio is given by

\mu = \frac{\frac{0.04}{30} }{\frac{change \ in \ length}{l_{o} } }

{\frac{change \ in \ length}{l_{o} } = \frac{\frac{0.04}{30} }{0.28}

{\frac{change \ in \ length}{l_{o} } = 0.00476

\frac{l_{1} - l_{o}  }{l_{o}  } = 0.00476

\frac{l_{1} }{l_{o} } = 1.00476

Final length l_{o} = 105.2 m

Original length

l_{o} = \frac{105.2}{1.00476}

l_{o} = 104.7 mm

This is the original length of the specimen.

5 0
3 years ago
Will this airplane stay in the air a long time? Why or why not?
iogann1982 [59]
Do you have a picture of the question?
7 0
2 years ago
Technician a s ays both an ohmmeter and a self-powered test light may be used to test for continuity. technician b says both may
amm1812

Both A and B technicians are correct because both might be used to test fuses, according to technician B.

<h3>What is continuity?</h3>

The behavior of a function at a certain point or section is described by continuity. The limit can be used to determine continuity.

From the question:

We can conclude:

The technician claims that you may check for continuity using both an ohmmeter and a self-powered test light. Both might be used to test fuses, according to technician B.

Thus, both A and B technicians are correct because both might be used to test fuses, according to technician B.

Technician A says both an ohmmeter and a self-powered test light may be used to test for continuity. Technician B says both may be used to test fuses. Who is correct?

Learn more about the continuity here:

brainly.com/question/15025692

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5 0
1 year ago
Express 2/16 in thirty-seconds
mafiozo [28]

Answer:

\frac{2}{16}  = \frac{4}{32} in thirty seconds.

Explanation:

one thirty second is one part out of 32 equal section . It is used to describe amounts accurately.

\frac{2}{16} can be easily expressed as \frac{4}{32}

3 0
2 years ago
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