8.17 Water is the working fluid in a Rankine cycle. Superheated vapor enters the turbine at 10 MPa, 4808C, and the condenser pre
ssure is 6 kPa. The turbine and pump have isentropic efficiencies of 80 and 70%, respectively. Determine for the cycle (a) the heat transfer to the working fluid passing through the steam generator, in kJ per kg of steam flowing. (b) the thermal efficiency. (c) the heat transfer from the working fluid passing through the condenser to the cooling water, in kJ per kg of steam flowing.
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Answer:
Load = 2.42 tons
Lifting speed = 24 RPM
Explanation:
Given that
Power=10 KW
Efficiency = 90%
So the actual power,P=0.9 x 10 =9 KW
Speed of motor = 1440 RPM
Diameter of drum = 300 mm
radius =150 mm
G=60:1
Lets take speed of drum =N
We know that
N=24 RPM
We know that
Where T is the torque
T=3580.98 N.m
Lets take load =F
So T= F x r
3580.98 = F x 0.15
F=23.87 KN
We know that
1 KN=0.109 tons
So 23.87 KN= 2.42 tons
So the load = 2.42 tons
Lifting speed = 24 RPM
Answer:
v = 40 m/s
Explanation:
Difference in the height of the two columns:
Air density,
Water density,
The velocity of air flow is given by the equation:
Answer:
78 MPa
Explanation:
Given that the critical resolved shear stress for a metal is 39 MPa, the maximum possible yield strength for a single crystal of this metal is twice the critical resolved shear stress for the metal. The maximum yield yield strength for a single crystal of this metal that is pulled in tension () is given as: