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maks197457 [2]
3 years ago
7

Rearrange the speed equation to solve for distance

Mathematics
1 answer:
pychu [463]3 years ago
4 0
When you are solving problems for distance, speed and time, you will find it helpful to use diagrams and/or charts to organize the information and help you solve the problem. You will also apply the formula that solves distance, speed/rate and time which is distance = speed/rate times time:
<span>d = rt</span>
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The rectangular prism shown has a length of 10 cm, a width of 10 cm, and a height of 6 cm. Find the length of the inner diagonal
melamori03 [73]
<h3>Answer:</h3>

15.36 cm

<h3>Explanation:</h3>

The Pythagorean theorem tells you ...

... AC² = AB² + BC² . . . . . relation for face diagonal

... AD² = AC² + CD² . . . . . relation for space diagonal

Subsituting the expression for AC² given by the first equation, the second equaiton becomes ...

... AD² = AB² + BC² + CD²

... AD² = (100 cm²) + (100 cm²) + (36 cm²) = 236 cm²

Taking the square root, we have ...

... AD = √236 cm = 2√59 cm

... AD ≈ 15.36 cm

8 0
3 years ago
A stereo can be bought for $200 down and payments of $62.70 each month for 12 month. Find the total cost of the stereo
Ede4ka [16]

Answer:

262.70

Step-by-step explanation:


4 0
2 years ago
I NEED HELP PLEASE QUICK!!
astraxan [27]

Answer:

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Here, for i.e, I'H'/IH = (8 + 4)/(4 + 2) = 12/6 = 2

Hope this helps!

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6 0
3 years ago
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Consider the derivation of the quadratic formula below. What is the missing radicand
Vedmedyk [2.9K]

Answer:

\frac{b^2 - 4ac}{4a^2}

Step-by-step explanation:

Given

See attachment for complete question

Required:

Complete step 6

At step 5, we have:

(x + \frac{b}{2a})^2 = \frac{b^2}{4a^2} - \frac{4ac}{4a^2}

Take LCM

(x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2}

Take square roots of both sides to get step 6

x + \frac{b}{2a} = \±\sqrt{\frac{b^2 - 4ac}{4a^2}}

Hence, the missing radicand is: \frac{b^2 - 4ac}{4a^2}

5 0
3 years ago
Which scenario best matches the graph below?​
faust18 [17]

Answer:

C

Step-by-step explanation:

I might be wrong but the best option I see would be C

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