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Leya [2.2K]
4 years ago
11

Given AC=DF,BC=DE Prove AB=EF

Mathematics
1 answer:
Shkiper50 [21]4 years ago
6 0

Answer:

Hope this helps

Step-by-step explanation:

AC=DF

AB+BC=DE+EF

*BC=DE*

AB+DE=DE+EF

AB=EF

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Answer:

B

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3 years ago
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Mamont248 [21]

Answer:

(a - b)^2 = 49 - 4b^2 +2ab

Step-by-step explanation:

Given: a^2 + b^2 = 7b (assuming A is really “a”)

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Plan: Use Algebraic Manipulation

Start with b^2 + (2b - a)^2 = 7^2 =>

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Double Check: recalculated ✅ ✅

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4 0
3 years ago
95 points <br><br> Simplify (4^9/4^3)^5 Show your work for full credit
dexar [7]

Answer:

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