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djverab [1.8K]
3 years ago
11

Use a calculator to find a value of θ between 0° and 90° that satisfies the statement. Write your answer in degrees and minutes

rounded to the nearest minute.
cot θ = 5.7885
Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

Answer:

(9° 48' 17")

Step-by-step explanation:

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1 millimeter equals how many meters
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there are .001 meters in 1 millimeter

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-10 = y/11 - 13<br><br> solve for y
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Answer:

10=y/11-13

We move all terms to the left:

-10-(y/11-13)=0

-y/11+13-10=0

We multiply all the terms by the denominator

-y+13*11-10*11=0

We add all the numbers together, and all the variables

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We move all terms containing y to the left, all other terms to the right

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3 years ago
Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes
lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 680 trials

            r = number of success  

           p = probability of success which in our question is 0.55

So, it means X <em>~ </em>Binom(n=680, p=0.55)

<em><u>Now, we have to find the mean and standard deviation of the given binomial distribution.</u></em>

  • Mean of Binomial Distribution is given by;

                    E(X) = n \times p

       So, E(X) = 680 \times 0.55 = 374

  • Standard deviation of Binomial Distribution is given by;

                   S.D.(X) = \sqrt{n \times p \times (1-p)}

                               = \sqrt{680 \times 0.55 \times (1-0.55)}

                               = \sqrt{680 \times 0.55 \times 0.45} = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

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3 years ago
The histogram shows the distributions of essay scores for high school sophomores and juniors in a contest. Which comparison of t
goblinko [34]

Answer:

A=Both distributions are nearly symmetric

Step-by-step explanation:

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