this gives
total area of the field = 4655 sqyrd + 1884.79 sqyrd = 6539.79 sqyrd
cost of fertilising 1 sqyrd = $ 0.08
so cost of fertilising 6539.79 sqyrd = 6539.79 * $ 0.08 = $ 523.18
Answer:
B
Step-by-step explanation:
x(2x + 3)
Expand the brackets.
x(2x)+x(3)
Multiply the terms.
2x² + 3x
The answer is 2x² + 3x.
Answer:
The correct option is;
Yes, the line should be perpendicular to one of the rectangular faces
Step-by-step explanation:
The given information are;
A triangular prism lying on a rectangular base and a line drawn along the slant height
A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces
Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).
Volume in terms of pi =V=πr2h
Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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