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DiKsa [7]
3 years ago
9

Solve the inequality. Show your work 6y -8 ≤ 10

Mathematics
2 answers:
emmainna [20.7K]3 years ago
6 0

6y-8≤10

Add 8 to both sides

6y-8+8≤10+8

Simplify

6y≤18

Divide both sides by 6

6y/6  ≤   18/6

Simplify

y  ≤ 3

prohojiy [21]3 years ago
4 0
6y - 8 ≤ 10   Add 8 to both sides
     6y ≤ 18   Divide both sides by 6
       y ≤ 3

Y is less than or equal to 3.

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I need help with this question please
Vsevolod [243]

Answer:

32

Step-by-step explanation:

times

4 0
3 years ago
What is the value of the expression <br> 3<br> 6 - (- 11.5)?<br> 4
Digiron [165]

Answer: 31 hope this helped

Step-by-step explanation: I'm assuming your problem looks like this: 4+5*6-3 =? To solve this problem you need to use the order of operations. PEMDAS which stands for Parentheses, exponents, multiply and divide, and lastly add and subtract. You must multiply and divide before you add and subtract so you must do 5*6 first. You now get 4+30-3. Now all you have left is addition and subtraction so you now just go from right to left and do one at a time. So 4+30 = 34 , 34-3=31. Therefore your answer should be 31. Hope that helped!

8 0
2 years ago
I need help on this question
kherson [118]

Answer:

A

Step-by-step explanation:

Just put x = 80 and y = 210 into the equation...

or put x = 40, y = 90.

A:

210 - 90 = 3(80-40)

120 = 120√

B:

210 + 90 = 3(80+40)

300 = 360×

C:

210 - 90 = 2.6(80-40)

120 = 104×

D:

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8 0
3 years ago
Two numbers are missing from this table. How can the missing numbers be
KiRa [710]

Answer:

multiply input number by 4

Step-by-step explanation:

In the figure attached, the problem is shown.

We can see the following values:

input = 1, output = 4*1 = 4

input = 4, output = 4*4 = 16

input = 7, output = 4*7 = 28

Then, the missing numbers can be found multiply input number by 4

3 0
2 years ago
Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.
azamat

Answer: i think  (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:

(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

= (16n² - 1)²

= 16².n².n² - 2.16.n² + 1

= 8n²(32n² - 4) + 1

can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

6 0
3 years ago
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