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Triss [41]
3 years ago
15

How do I find x on a quadrilateral

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0
<span>n stands for the number of sides, which is 4.To find the sum of the angles, subtract 2 from the number of sides and multiply by 180.Add all the angles together and set that equal to 360 to solve for x.<span>Plug 32 ° in for x to find the measures of the angles.</span></span>
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Find the distance between the given points. Round to the nearest tenth.
sashaice [31]

Answer:

B and is (-2, 3)...........

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2 years ago
9 times the sum of 8 and y​
Naya [18.7K]

Answer:

9(8+y)

Step-by-step explanation:

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8 0
3 years ago
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The Japanese 5 yen coin has a hole in the middle.
alexandr402 [8]

Answer:

Subtract the two diameters and multiply by 0.5

Step-by-step explanation:

Calculating the Radius of the hole gives distance to the inner edges WHILE the Radius of the coin gives us the distance to the outer edges.

By subtracting the output we can then get the difference between both distances.

If hole diameter = 5mm and coin diameter = 22mm

Difference = [(22 - 5)mm] ÷ 2

17mm / 2 = 8.5mm

5 0
3 years ago
Which of the following are roots of the polynomial function? Check all that apply.
lutik1710 [3]

You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.

It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are

... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2

The appropriate choices are

... C. (3-√29)/2

... D. (3+√29)/2

... F. 3

_____

The quadratic formula tells you the solution to

... ax²+bx+c=0

is x = (-b±√(b²-4ac))/(2a)

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8 0
2 years ago
Solve the compound inequality,
Feliz [49]

Answer:

\large\boxed{y\in(-6,\ \infty)}

Step-by-step explanation:

(1)\\2y-2>-14\qquad\text{add 2 to both sides}\\\\2y-2+2>-14+2\\\\2y>-12\qquad\text{divide both sides by 2}\\\\\dfrac{2y}{2}>\dfrac{-12}{2}\\\\y>-6

(2)\\\\4y-4\geq12\qquad\text{add 4 to both sides}\\\\4y-4+4\geq12+4\\\\4y\geq16\qquad\text{divide both sides by 4}\\\\\dfrac{4y}{4}\geq\dfrac{16}{4}\\\\y\geq4

\text{From (1) and (2) we have:}\\\\y>-6\ or\ y\geq4\to y\in(-6,\ \infty)\ \cup\ [4,\ \infty)\Rightarrow y\in(-6,\ \infty)

7 0
3 years ago
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