"X is partly constant and partly varies as y"
---> x = ky + p
when y=2,x=30 ---> 30 = 2k + p
when y=6,x=50 ---> 50 = 6k + p
subtract: 20 = 4k
k = 5
sub back in the first: 30 = 10+p
p = 20
x = 5y + 20
now you can answer B
notice this is just a variation of y = mx + b
Answer:
44.7
Step-by-step explanation:
Speed = distance / time
speed from distance a to b = 50 = 10 / time
time = 10/50 = 12 minutes
Speed from a to c = 62 = distance / 30 minutes
distance = 62 x 0.5 = 31 m
diatance from b to c = 31 - 10 = 21
time = 30 - 12 = 28 minutes
speed = 21 / 28 minutes
31 / 0.47
Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
Answer:
Step-by-step explanation:
The first step is to determine the areas of the inner and the bigger circles.
The formula for determining the area of a circle is expressed as
Area = πr²
Where
r represents the radius of the circle.
π is a constant whose value is 3.14
Considering the inner circle,
diameter = 148.4 cm
Radius = 3 inches
Area = 3.14 × 3² = 28.26 inches²
Considering the bigger circle,
Radius = 7 inches
Area = 3.14 × 7² = 153.86 inches²
The area between the bigger and inner circles is
153.86 - 28.26 = 125.6 inches²
Probability = number of favourable outcome/number of total outcome.
the probability you land inside the bigger circle but outside smaller circle is
125.6/153.86 = 0.82
