3 years ago

Which equation is correct?

1 answer:

7 0

The answer is d.

cot x=adjacent over opposite
secant x=hypotenuse over adjacent

I hope this helps!
Best wishes.
-HuronGirl

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2d=a-b/b-c - solve for a

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$2d=\frac{a-b}{b-c}\\\\\frac{a-b}{b-c}=2d\ \ \ \ \ |multiply\ both\ sides\ by\ (b-c)\\\\a-b=2d(b-c)\ \ \ \ |add\ "b"\ to\ both\ sides\\\\\boxed{a=2bd-2cd+b}$

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3 years ago

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Step-by-step explanation:

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3 years ago

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quester [9]

Answer:

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Step-by-step explanation:

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3 years ago