Answer:
f(119) is 571
Step-by-step explanation:
first you substitute the n's for 119, because n is the nth term, or which position term you are looking for.
then you will get f(119) = f(119-1) +4
simplify to f(119) = f(118) +4
(I'm not too familiar with the recursive formula but I can assure you that I have the right answer, it just may be confusing when reading my explanation.)
understand that the first number in this sequence is 99. meaning from 99 onward, you will need 118 more terms to reach the 119th term. since the gap between each term ( called the common difference or "d" in this case is +4, we can multiply 118+4.
this will get you to 472. but that's not it, you have to add the first term, which is 99 back on.
then it will get you the answer of 571.
I can prove this by using the explicit formula,
f(119) = f(1) + d (n-1)
f(119) = 99 + 4 (119-1)
f(119) = 99 + 4 (118)
f(119) = 99 + 472
f(119) = 571
