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Paladinen [302]
3 years ago
12

The answer to a question is [MLT^-1. The question is what are the dimensions of

Physics
2 answers:
Llana [10]3 years ago
6 0

The question is a little light on introductory explanation.  In fact, there isn't any that I can see.

The way I understand it, [ M L T⁻¹ ] means the PHYSICAL DIMENSIONS of  (Mass)·(Length)·(1/Time).  Then, the choices are expressions of various quantities that you run into in Physics ... like 'mvr' means 'mass·velocity·radius', 'mat' means 'mass·acceleration·time' etc. ... and it wants to know which one of the choices would end up having the dimensions of  [ M L T⁻¹ ] ?

I'm not going to go through all of them, but here's one:

Take 'm·v·r' :  'm' is a mass.  The 'v' is a velocity, so it's something like (meters)/(sec), which is dimensions of (length) / (time) or [ L·T⁻¹ ]. The 'r' is radius, so it has dimensions of length [ L ].

The whole product of 'm·v·r' has dimensions of [M] · [L·T⁻¹] · [ L ].  Multiply that out, and it's [ M L² T⁻¹ ] .  That's NOT the dimensions that the question is asking for  [ M L T⁻¹ ]   so the answer isn't choice-A  'm v r' .

I believe it's going to turn out to be choice-B .  ' m·a·t ' .  The 'a' is acceleration.  That's like (meters)/(sec²), so the dimensions of acceleration are [ L T⁻² ] .  I'm sure you can carry the ball from this point.

 

Valentin [98]3 years ago
5 0
I hope this helps. Your answer is D

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Makovka662 [10]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Gravitational Force between given objects will be ~

  • 9.34 \times  {10}^{ - 6}  \:  \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where ~

  • F = gravitational force

  • m_1 = mass of 1st object = 70 kg

  • m_2 = mass of 2nd object = 2000 kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 1 m

Let's calculate the force ~

  • F =  \dfrac{6.674 \times 10 {}^{ - 11} \times 70 \times 2000 }{1 {}^{2} }

  • F =6.674 \times 7 \times 2 \times 10 { }^{ - 11} \times 10 {}^{4}

  • 93.436 \times 10 {}^{ - 7}

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Why don't the two forces in Newton's third law cancel each other? They act in the same direction. They are different kinds of fo
pogonyaev

Answer:They act on different bodies

Explanation:

Newton's third law of motion states that for every action there is equal and opposite reaction i.e. action and reaction. Though action and reaction are equal they act in different bodies that is why they do not cancel out each other.

For example, a block of mass m placed over the table exerts a force of mg to the table while the table applies a Normal reaction of equal magnitude as of mg to the block of mass m.

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Answer:

Explanation:

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After an instant, the velocity of the second cart is U2=-2.8m/s

Now after collision the two cart move together with the same velocity I.e inelastic collision

Using conservation of momentum

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