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3 years ago

13

Hamid is going to heat sodium chloride and water in a beaker. How can he carry out his experiment as

1 answer:

wolverine [178]3 years ago

4 0

Answer:

he can wear gogles lab coat and gloves

Explanation:

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In a photoelectric experiment it is found that a stopping potential of 1.00 V is needed to stop all the electrons when incident

kiruha [24]

Answer:

Planck’s constant is $6.9*10^{-34} Js$

work function of metal is $5.846*10^{-19}$

Explanation:

The maximum kinetic energy from electron from photoelectric effect is given by

$\K_{max}=eV_o$ where $V_o$ is applied voltage and e is charge on electron and substituting charge on electron by $1.6*10^{-19}$ and 1.00 V for $V_o$

$K_{max}=1.6*10^{-19}*1=1.6*10^{-19} J$

Considering that the wavelength, \lambda of light used is given as $278*10^{-9} m$

Energy of light is given by

$E=\frac {hc}{ \lambda}$ where $\lambda$ is the wavelength, h is Planck’s constant and c is speed of light. Taking c for $3*10^{8} m/s$

Substituting values of wavelength and speed of light we obtain

$E=\frac {h*3*10^{8}}{278*10^{-9}}=h1.07914*10^{15} J$

If work function is $\phi$ then

$E=\phi + k_{max}$ hence

$h1.07914*10^{15} J=\phi +1.6*10^{-19} J$ ------- Equation 1

Energy corresponding to wavelength of 207 nm is

$E=h\frac {3*10^{8} m/s}{207*10^{-9}}=h(1.45*10^{15}}) J$

Maximum kinetic energy of electrons when $V_o$ is 2.6 V becomes

$K_{max}=(1.6*10^{-19})*2.6V=4.16*10^{-19} J$

From $E=\phi + k_{max}$ and substituting $h(1.45*10^{15}}) J$ for E and $4.16*10^{-19} J$ for $K_{max}$ we have

$h(1.45*10^{15}}) J=\phi +4.16*10^{-19} J$ ------ Equation 2

Equation 2 minus equation 1 gives

$h3.71*10^{14}=2.56*10^{-19}$

$h=\frac {2.56*10^{-19}}{3.71*10^{14}}\approx 6.9*10^{-34} Js$

Therefore, Planck’s constant is $6.9*10^{-34} Js$

Recalling equation 1 and substituting back the value of h as obtained

$h1.07914*10^{15} J=\phi +1.6*10^{-19} J$

$(6.9*10^{-34})*(1.07914*10^{15})=\phi +1.6*10^{-19} J$

$\ph=(6.9*10^{-34})*(1.07914*10^{15})-(1.6*10^{-19})=5.846*10^{-19}$

Therefore, work function of metal is $5.846*10^{-19}$

5 0

4 years ago

What is this object? Explain how it works and which one of Newton’s laws this represents.

lyudmila [28]

Answer:

the object is called Newton's cradle balance ball you can search it on Google

4 0

3 years ago

Whether or not incoming information is perceived as meaningful influences one's attention to it. T F

sergeinik [125]

This would be True. Hope this helps! :)

6 0

3 years ago

Read 2 more answers

Write one general properties of non contact force

Gekata [30.6K]

Answer: Gravitational force between the two masses does not depend on the medium separating two masses.

3 0

3 years ago

Hi please answer and show your work

jek_recluse [69]

Answer:

$\huge\boxed{\sf P.E. = 240\ MJ}$

$\huge\boxed{\sf K.E. = 19.6\ MJ}$

Explanation:

<u>Given:</u>

Mass = m = 200,000 kg

Vertical Distance = h = 120 m

Speed = v = 14 m/s

Acceleration due to gravity = g = 10 m/s²

<u>Required:</u>

1) Gravitational Potential Energy = P.E = ?

2) Kinetic Energy = K.E. = ?

<u>Formula:</u>

1) P.E. = mgh

2) K.E. = $\displaystyle \frac{1}{2} mv^2$

<u>Solution:</u>

1) P.E. = (200,000)(10)(120)

P.E. = 240,000,000 Joules

P.E. = 240 Mega Joules

P.E. = 240 MJ

2) K.E. = 1/2 (200000)(14)^2

K.E. = (100000)(196)

K.E. = 19,600,000 Joules

K.E. = 19.6 MJ

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

4 0

3 years ago