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Murljashka [212]
3 years ago
9

A car traveling 35 km/hr accelerates to a speed of 45 km/hr in .25 hr. What is its acceleration

Physics
1 answer:
ahrayia [7]3 years ago
6 0

Answer:

a=40Km/hr^2

Explanation:

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The velocity of a projectile at launch has a horizontal component vh and a vertical component vv. When the projectile is at the
Usimov [2.4K]

Answer:

- horizontal component of the velocity: v_h (because it is constant)

- vertical component of the velocity: 0

- vertical component of the acceleration: -g=-9.8 m/s^2 (downward)

Explanation:

The motion of a projectile consists of two independent motions:

- Along the horizontal direction, there are no forces acting on the projectile (if we neglect air resistance), therefore the horizontal acceleration is zero and the horizontal component of the velocity, vh, is constant

- Along the vertical direction, there is only one force acting on the projectile: the force of gravity, downward, which produces a constant downward acceleration of g=9.8 m/s^2. As a consequence, the vertical component of the velocity changes according to

v_v(t) = v_v-gt

where vv is the initial vertical velocity and t the time. According to this equation, the vertical component of the velocity decreases first, then becomes zero at the point of maximum height, then becomes negative (= changes direction and points downward)

So, in summary, at the highest point of the trajectory we have:

- horizontal component of the velocity: v_h (because it is constant)

- vertical component of the velocity: 0

- vertical component of the acceleration: -g=-9.8 m/s^2 (downward)

3 0
3 years ago
A 2.00-kg box is suspended from the end of a light vertical rope. A time-dependent force is applied to the upper end of the rope
Alex

Answer:

T = 27.92 N

Explanation:

For this exercise let's use Newton's second law

      T - W = m a

The weight

      W = mg

The acceleration can be found by derivatives

     a = dv / dt

     v = 2 t + 0.6 t²

     a = 2 + 0.6 t

We replace

      T - mg = m (2 + 0.6t)

      T = m (g + 2 + 0.6 t)               (1)

Let's look for the time for the speed of 15 m / s

       15 = 2 t + 0.6 t²

       0.6 t² + 2 t - 15 = 0

We solve the second degree equation

        t = [-2 ±√(4 - 4 0.6 (-15))] / 2 0.6

        t = [-2 ±√40] / 1.3 = [-2 ± 6.325] / 1.2

We take the positive time

       t = 3.6 s

Let's calculate from equation 1

       T = 2.00 (9.8 + 2 + 0. 6  3.6)

        T = 27.92 N

4 0
3 years ago
Plz, help the rubber ball be dropped from the top of a ladder. It bounces on the same spot on the ground several times to a less
Vladimir [108]

Answer:

What do you mean?

Explanation:

6 0
3 years ago
A rock at the top of a 20 meter tall hill.The rock has a mass of 10 kg. How much potentail   energy does it have?
ch4aika [34]
P.E.=mgh
= 10x10x20
=2000J
6 0
3 years ago
A 900-N lawn roller is to be pulled over a 5-cm (high) curb. Radius of roller is 25 cm. What minimum pulling force is needed if
Feliz [49]
I believe b 30 degrees 
8 0
3 years ago
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