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dedylja [7]
3 years ago
8

A wire of length L is wound into a square coil with 167 turns and used in a generator that operates at 60.0 Hz and 120 V rms val

ue in a 0.041-T magnetic field. What is the length L of the wire used to construct the coil
Physics
1 answer:
Mrac [35]3 years ago
8 0

Answer:

171.43m

Explanation:

First, define emf( electromotive force )-is the unit electric charge imparted by an energy source. In this case the generator.

The peak emf is:

E_p_e_a_k=\sqrt2(E_m_a_x)=\sqrt(2\times 120V)=170V

Substituting w=2\pi f and the value for peaf E gives:

Total length=4\sqrt {\frac{NE_p_e_a_k}{Bw}=4\sqrt{\frac{167\times 170}{0.041T\times 2pi \times 60.0Hz}

=171.43m

Hence, wire's length is 171.43m

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Hello!

Which nuclei is NOT radioactive?

A) Am-241 B) Mg-24 C) Pu-241 D) U-238

Solving:

It is noteworthy that chemical elements located on the periodic table in the lanthanide and actinide groups are radioactive.  

Am-241 (americium) belongs to the group of actinides and is a heavy and radioactive metal.  

Mg-24 (magnesium) is an essential element for the body, mainly for the nervous system, in addition to synthesizing proteins and serves for hormonal control, belongs to the group of alkaline earth metals and is a non-radioactive nucleus.

Pu-241 (plutonium) is an element that is isotope of fission by plutonium, belongs to the group of actinides and is a heavy and radioactive metal.  

U-238 (uranium) is an element that is isotope of non-fission uranium, belongs to the group of actinides and is a heavy and radioactive metal.

Answer:

B) Mg-24

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