All categories

3 years ago

If 17 ounces of cocoa are needed for 6 cookies, how many ounces of cocoa is needed for 8 cookies?

Mathematics

1 answer:

DENIUS [597]3 years ago

5 0

Answer:

22 and 2/3

Step-by-step explanation:

17/6= 2.8333333

2.8333333333 multiplied by 8= 22.66666666 or 22 and 2/3

You might be interested in

A number increased by 6 and the result divided by 3 is 21. what is the number?

kogti [31]

Answer:

Step-by-step explanation:

let the number be x

(x+6)/3 =21

x+6=21*3

x+6=63

x=57

7 0

2 years ago

Read 2 more answers

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

The bases of a trapezoid are 11 meters and 14 meters. Its height is 10 meters. What is the area of the trapezoid?

kenny6666 [7]

Area of Trapezoid = (1/2) * (Sum of bases) * height

Area = (1/2) * (11 + 14) * 10

= (1/2) * 25 * 10 = 5 *25 = 125

Area = 125 m²

4 0

3 years ago

What is 10th term in 3,8,13,18?

skad [1K]

3+5=8+5=13 so if you keep doing this you will get 48 which is the answer

5 0

3 years ago

Select all the correct tables.

Ymorist [56]

Answer:

middle left

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers