<h2>
Hello!</h2>
The answer is:
The point that is a solution to the system of inequalities is C(4,2).
<h2>
Why?</h2>
To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.
We are given the inequalities:


So, substituting the given points into the given inequalities, we have:
- A. (2,1)
Substituting into the first inequality, we have:

Substituting into the second inequality, we have:





Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.
- B. (-2,-1)
Substituting into the first inequality, we have:

Substituting into the second inequality, we have:




Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.
- C. (4,2)
Substituting into the first inequality, we have:

Substituting into the second inequality, we have:




Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.
- D(1,3)
Substituting into the first inequality, we have:

Substituting into the second inequality, we have:




Therefore, since 3 is not less than 0, and 3 is not less than -2, the point D(1.3) is not a solution to the system of inequalities.
Hence, the point that is a solution to the system of inequalities is C(4,2).
Have a nice day!