Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
-12+20=a(0+2)^2
8=4a
a=2
Equation:
y+20=2(x+2)^2
y+20=2(x^2+4x+4)
f(x)=2(x^2+4x+4)-20
f(x)=2x^2+8x+8-20
f(x)=2x^2+8x-20
Answer:
x= 8.5 and y= 2
Step-by-step explanation:
we conclude that the linear equation represented by the given table is:
y = (1/2)*x + 2
<h3>
Which function is the one described by the table?</h3>
A general linear equation is given by:
y = a*x + b
Where a is the slope and b is the y-intercept.
If the line passes through (x₁, y₁) and (x₂, y₂), then the slope is given by:

Here we can use just the first two points on the given line:
(-8, -2) and (-4, 0)
Then the slope will be:

Then the linear equation is something like:
y = (1/2)*x + b
To find the value of b, we can use one of the two given points, I will use (-4, 0), then:
0 = (1/2)*(-4) + b
0 = -2 + b
2 = b
Then we conclude that the linear equation represented by the given table is:
y = (1/2)*x + 2
Then the correct option is the first one.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:15/27(third option is the correct answer)