Given:
Perimeter of a football field = 920 feet.
The width is 60 feet more than one-third of the length.
To find:
The dimensions of a football field.
Solution:
Let the length of the field be x.
Then, width = 
We know that,




Subtract both sides by 120.


Multiply both sides by 3.

Divide both sides by 8.

Now,




Therefore, the length and width of the football field are 300 feet and 160 feet respectively.
-4.9t^2 + 6.1t - 0.8 = 0
Subtract 3 from both sides
To find the GCF, you have to list all factors of each number and find the first common one.
12 = 1, 2, 3, 4, 6, 12
28 = 1, 2, 4, 7, 14, 28
36 = 1, 2, 3, 4, 6, 9, 12, 18, 36
the GCF of numbers 12, 28, 36 is 4.
hope this helps, God bless!
We have that
x² − 8xy + y²<span> = 8
</span>2x-8y-8x(dy/dx)+2y*(<span>dy/dx)=0
</span>8x(dy/dx)-2y*(dy/dx)=2x-8y
[8x-2y]*(dy/dx)=2x-8y
(dy/dx)=[2x-8y]/[8x-2y]
(dy/dx)=2*[x-4y]/2*[4x-y]
(dy/dx)=[x-4y]/[4x-y]
the answer is
(dy/dx)=[x-4y]/[4x-y]