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2 years ago

Which number should she subtract from both sides of the equation?

Mathematics

1 answer:

bezimeni [28]2 years ago

7 0

Where’s the problem where it explains what’s she is subtracting?

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Please help.<br> If you could put your work in the answer that would<br> Be greatly appreciated.

AleksandrR [38]

Answer:

38°

because it is equal.

GJ=21

JH=21

GJ=JH

∠GFJ =∠HFJ

∠GFJ =38°

∠HFJ=38°

6 0

2 years ago

(a) Show that a differentiable function f decreases most rapidly at x in the direction opposite the gradient vector, that is, in

Serhud [2]

Answer:jjkhlnk

Step-by-step explanation:

7 0

2 years ago

Investigate how demand elasticities are affected by increases in demand. Apply the midpoint formula to calculate the demand elas

inn [45]

It should be noted that a good that has a high demand elasticity for an economic variable implies that consumer demand for that good is more responsive to changes in the variable.

<h3>How to explain the demand?</h3>

It should be noted that an elastic demand is one werr the change in quantity demanded due to a change in price is large.

Also, an inelastic demand is one in which the change in quantity demanded due to a change in price is small. When the formula creates an absolute value greater than 1, the demand is elastic.

Here, a good that has a high demand elasticity for an economic variable implies that consumer demand for that good is more responsive to changes in the variable.

Learn more about demand on:

brainly.com/question/1245771

#SPJ1

6 0

10 months ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$

8 0

2 years ago

Read 2 more answers

Write the following expression in expanded form 3(4y+x-8)

Makovka662 [10]

12y+3x-24 you times everything in the bracket by 3

3 0

2 years ago

Read 2 more answers