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Lostsunrise [7]
3 years ago
13

I need help with this. I've tried to type out this problem, but it comes out wrong, so I uploaded a picture:

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

answer: 6.4

work:

Solve the problem.

Let's start by solving the numerator,

(5 + 3)² <em>step one: add 5 + 3 </em>

(8)² <em>step two: simplify 8²</em>

64

now, let's simplify our denominator

1 + 2⁵ - 23 <em>step one: simplify 2⁵.</em>

1 + 32 - 23 <em>step two: add 1 + 32.</em>

33 - 23 <em>step three: subtract 33 - 23</em>

10.

now, put the numerator back over the denominator.

64/10

let's simplify by dividing, we get 6.4.

<em>i hope this helps, and have a great day! don't hesitate to ask if you need more help with this specific question! ♥ - eviezoom </em>


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6 0
3 years ago
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

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Applying Pythagoras theorem

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Therefore

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To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

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One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

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Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

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dz/dt = 4624/68

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