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larisa86 [58]
3 years ago
11

14.Which of the following exhibit maximum paramagnetic behaviour – Fe3+ or

Chemistry
1 answer:
Naddik [55]3 years ago
5 0

Answer:

Fe^3+

Explanation:

The electron configuration for Fe^3+ is; 1s2 2s2 2p6 3s2 3p6 3d5

The electron configuration for Ni^2+ is; 1s2 2s2 2p6 3s2 3p6 3d8

Now it is pertinent to recall that the 3d sublevel has a maximum occupancy of ten electrons. These ten electrons occupy a set of five degenerate orbitals. Having said that, it is clear that Ni^2+ ion will have two unpaired electrons while Fe^3+ will have five unpaired electrons.

Let us also not forget that paramagnetism has to do with the presence of unpaired electrons. That means that maximum paramagnetism refers to the presence of maximum number of unpaired electrons.

Since Fe^3+ has the greatest number of unpaired electrons among the duo, Fe^3+ will exhibit a maximum paramagnetic behavior.

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The volume of the gas is 180.26 L, if there are 63.5 mol of an ideal gas at 9.11 atm at 42.80 °C.

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After rearranging the aforementioned expression, the volume might then be found as: V= n R T/ P.

Consequently, V= 63.5 mol, 0.0821, 315 K, and 9.11 atm equal 180.26 L.

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The ideal gas equation is PV = nRT. In this equation, P denotes the ideal gas's pressure, V its volume, n its total amount, expressed in moles, and R its resistance for the universal gas constant, and T for temperature.

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