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3 years ago

Help and plz explain for i can understand and will remember how to do it and DC for i can put on my notes

Mathematics

2 answers:

Pie3 years ago

6 0

$\dfrac{3}{14}:\dfrac{7}{10}= \dfrac{3}{14}\cdot\dfrac{10}{7}= \dfrac{3}{7}\cdot\dfrac{5}{7}=\dfrac{15}{49}$

zaharov [31]3 years ago

5 0

Answer in the document below.

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an owl travels 8 1/3 miles an hour and a seagull travels 12 1/2 miles in 2/3 hour. which animal is faster?

Simora [160]

Seagull because the owl has 5 5/9 and the sea 8 1/3

5 0

3 years ago

Read 2 more answers

Find the equation of a line that passes through the point (4,2) that is perpendicular to the line y=4/3 x

Mrac [35]

Answer:

$y=\frac{3}{4}x-1$

Step-by-step explanation:

Since we're looking at perpendicular lines, the slope of the new line is the reciprocal of the original line.

So the slope of our new line is $\frac{3}{4}$

So far, we are looking at $y=\frac{3}{4} x+b$

Now we need to find the b value by plugging in the given point.

$2=\frac{3}{4}(4)+b\\ 2=3+b\\ b=-1$

So the final equation is $y=\frac{3}{4}x-1$

8 0

3 years ago

Helen rolls a dice and flips a coin.<br> Calculate the probability that she will get a 4 and a tail.

Rom4ik [11]

Answer:

1/12

Step-by-step explanation:

The probability that Helen will roll a 4 is 1/6 the probability that she will get tails is 1/2. Multiply those two events together to find the probability of P(A and B)

5 0

3 years ago

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Square A is a scaled version of square B. The dimensions of square A are three times the dimensions of square B. The area of squ

denis23 [38]

Answer:

The side of square A is 30 cm.

Step-by-step explanation:

Given that,

The dimensions of square A are three times the dimensions of square B.

The area of square A is 900 sq cm.

Side of square A = 3( side of square B)

Let the side of square B is b. So,

Side of square A, a = 3b

We know that, the area of square is side². So,

$(3b)^2=900\\\\9b^2=900\\\\b^2=100\\\\b=10\ cm$

Side of square A, a = 3(10) = 30 cm

Hence, the side of square A is 30 cm.

8 0

3 years ago

When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of

makkiz [27]

Answer:

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So $A(t) \alpha \sin (\frac{t - \alpha }{k} )$

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

$A(t) = 2.2\sin \frac{(t)}{k} + 0.6$

at t = 2 sec volume of a is 0.6

So function reduce to

$A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6$

and t = 5 max value of volume is represent

so,

$\sin \frac{t - \alpha }{k} = 1$

$\frac{t - 2}{k} = \frac{\pi }{2}$ when t = 5

$\frac{6}{\pi } = k$

so the equation becomes

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

7 0

3 years ago