An complementary angle = 90°
one of the angles is twice as large as the smaller one
let the larger angle be x, and the smaller = y
x = 2(y)
x + y = 90
Plug in 2y for x
2y + y = 90
simplify, combine like terms
2y + y = 90
3y = 90
isolate the y, divide 3 from both sides
3y/3 = 90/3
y = 90/3
y = 30
plug in 30 for y in the equation x + y = 90
x + (30) = 90
isolate the x, subtract 30 from both sides
x + 30 (-30) = 90 (-30)
x = 90 - 30
x = 60°
The measurement of the larger angle is 60°
hope this helps
In geometry, a line segment<span> is a part of a </span>line<span> that is bounded by two distinct end points, and contains every point on the </span>line<span> between its endpoints. A closed </span>line segment<span> includes both endpoints, while an open </span>line segment<span> excludes both endpoints; a half-open </span>line segment<span> includes exactly one of the endpoints.</span>
Day = 8 4/5 ÷ 4
day = 44/5 ÷ 4
day = 44/5 × 1/4
day = 44/20
day = 11/5
day = 2 1/5
The answer to your is 100 volts
Answer:
m<H = 62°
Step-by-step explanation:
If FG is congruent to HF, it means their opposite angles are also congruent to each other. This implies that, <H = <G. Thus, ∆FGH is an isosceles triangle with base angles <F and <G.
Given that m<F = 56°, therefore:
56° + 2(m<H) = 180° (sum of triangle)
2(m<H) = 180° - 56°
2(m<H) = 124°
m<H = 124/2
m<H = 62°
