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netineya [11]
3 years ago
6

How many 5.6 kg are in g

Mathematics
2 answers:
Sauron [17]3 years ago
6 0

Answer:

5600g

Step-by-step explanation:

Multiply by 1000 to convert from kg to gram

polet [3.4K]3 years ago
3 0

Answer:5600

Step-by-step explanation:

multiply the mass value by 1000

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When asked to rewrite the expression (x3 + 2x? – x)-(-x3 + 2x2 + 6), Denise made a mistake. She did not get the correct answer,
DanielleElmas [232]

Answer:

She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6

Step-by-step explanation:

It looks like she didn't fully distribute the -

(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original

x3+ 2x2 - x + x3 – 2x2 +6 :Changed

~

(x3 + 2x2 - x)-(-x3 + 2x2 + 6)

x3 + 2x2 - x + x3 - 2x2 - 6

x3 + x3 + 2x2 - 2x2 -x - 6

2x3-x-6

I hope this helps ^-^

3 0
2 years ago
Last year, a toy company made $14,476,375 from sales of a stuffed animal pillow.
Anna [14]
14,000,000 is the answer please give me points
7 0
3 years ago
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It took the carriage 2.5 hours to travel 20 miles. H ow long will it take for the carriage to travel in 12 miles
Tomtit [17]
\bf \begin{array}{ccll}
hours&miles\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2.5&20\\
h&12
\end{array}\implies \cfrac{2.5}{h}=\cfrac{20}{12}\implies \cfrac{2.5\cdot 12}{20}=h
6 0
3 years ago
What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

8 0
3 years ago
Coordinates will be fine PLs ASAP cause I need this rn<br> 13 POINTS!!!
grigory [225]

If the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Given,

The vertices of the triangle = J(-3,-5), K(-2,2) and L(1,-4)

We know,

In reflection in y axis (x,y)  will become (-x,y)

Then the vertices of the reflection in y axis = J(3,-5), K(2,2) and L(-1,-4)

Draw the triangle using the vertices.

Hence, if the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Learn more about reflection here

brainly.com/question/15487308

#SPJ1

3 0
1 year ago
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