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4 years ago

Which function has the same range as y = csc x?

Mathematics

2 answers:

Harman [31]4 years ago

5 0

The answer is B.) Y = sec X.

Salsk061 [2.6K]4 years ago

3 0

Answer:

Option B is the correct answer.

Step-by-step explanation:

cosce x = 1/ sinx

sec x = 1/cosx

We know that the range of cosx and sinx lies in between -1 and 1.

The both have the same range.

Since they both have the same range their reciprocal will also be having same range.

So cosecx and secx have same range.

Option B is the correct answer.

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29. A DVD player has a list price of $120. The

kvv77 [185]

Answer:

$90

Step-by-step explanation:

First the given is the listed price of DVD which is 120 dollars.

Now we need to find out what the price will be after discount of 25%

To do this we will have to convert the percentage to decimal by moving decimal 2 place left and removing percentage sign which will become 0.25.

Then we multiply by the listed price which is 120

so 120*0.25=30

so we subtract 30 by original price cause that is the discount off we are receiving

120-30=90

so 90 will be the sale price after 25% discount.

8 0

3 years ago

Make for me number 21 thx

xz_007 [3.2K]

Method One

You could divide by 5 right away.

20/5 = - 3 + x

4 = - 3 + x Add 3 to both sides.

4 + 3 = x

x = 7

Method Two.

You could remove the brackets. This is slightly longer, but some questions can only be solved that way.

20 = 5(-3) + 5x

20 = -15 + 5x Add 15 to both sides

20 + 15 = 5x

35 = 5x Divide by 5

35/5 = x

7 = x

8 0

3 years ago

What integer does Point A represent?<br><br> 20 points!!

Dima020 [189]

Answer:

The integer 'A' represents -8.

6 0

3 years ago

Read 2 more answers

. The time required for a technician to machine a specific component is normally distributed with a mean of 2 hours and a standa

erma4kov [3.2K]

Answer:

a) There is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

b) There is a 0.42% probability that the technician will require at least 2.75 hours to complete one component

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have to be careful. The mean is in hours, while the standard deviation is in minutes. I am going to work with both in hours, as the problem states. 17 minutes is 0.283 hours, so:

$\mu = 2, \sigma = 0.283$

(a.) What is the probability that the technician can machine one component in 1.5 hours or less?

This probability is the pvalue of the Zscore when $X = 1.5$ . So:

$Z = \frac{1.5 - 2}{0.283}$

$Z = \frac{-0.5}{0.283}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

(b.) What is the probability that the technician will require at least 2.75 hours to complete one component?

The pvalue of the score of $X = 2.75$ is the probability that the technican will require less than 2.75 hours to complete one component. The probability that he will require at least 2.75 hours to complete one component is 1 subtracted by this pvalue. So: