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3 years ago

Which function has the same range as y = csc x?

Mathematics

2 answers:

Harman [31]3 years ago

5 0

The answer is B.) Y = sec X.

Salsk061 [2.6K]3 years ago

3 0

Answer:

Option B is the correct answer.

Step-by-step explanation:

cosce x = 1/ sinx

sec x = 1/cosx

We know that the range of cosx and sinx lies in between -1 and 1.

The both have the same range.

Since they both have the same range their reciprocal will also be having same range.

So cosecx and secx have same range.

Option B is the correct answer.

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1/3 ÷ 3/8<br><br>O 8/9 <br>O 1 1/8 <br>O 1/8

ZanzabumX [31]

Answer:

the answer is A. 8/9

Step-by-step explanation:

i did the math

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3 years ago

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ella [17]

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3 years ago

The graph of a system of equations with the same slope will have no solutions. (1 point)

Viefleur [7K]

I don’t really get what you’re asking here but a system of 2 parallel lines has no solution, and a system of 2 parallel lines is called inconsistent.

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3 years ago

Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

8 0

3 years ago

pls helpppp c=30m+50 and c=20m+100. solve for c and show your work.

Contact [7]

Answer:c=200

Step-by-step explanation:

30(5) + 50 = 200

20(5) + 100 = 200

-------------------------------|

100 30m

- 50 - 20m

——— ———

50 10m 50/10 = 5 [m=5]

7 0

3 years ago