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patriot [66]
3 years ago
11

A worm is at the bottom of a 10ft hole. He starts climbing out of the hole, climbing 3 feet in one hour. Then he takes a break f

or 1 hour and slides backward 1 foot. He repeats this pattern, climbing at a constant rate of 3 feet per hour and then sliding backward for an hour until he reaches the top. If the worm begins crawling at 9 am, what time will he reach the top of the hole.
Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

6:00pm is the answer

Step-by-step explanation:


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Answer:

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Step-by-step explanation:

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goldenfox [79]

Answer: y = -14/9(x + 4)^2 + 7

Step-by-step explanation:

The given roots of the quadratic function is (-1, -7)

The vertex is at (-4, 7)

The formula is

y = a(x - h)^2 + k

The vertex is (h, k)

Comparing with the given vertex, (-4, 7), h = -4 and k = 7

Substituting into the formula

y = a(x - h)^2 + k, it becomes

y = a(x - - 4)^2 + 7

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x = -1 and y = -7

Substituting x = -1 and y = -7 into the equation,

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-7 = a(-1+4)^2 + 7

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y = -14/9(x + 4)^2 + 7

8 0
3 years ago
A ball is thrown from an initial height of 3 feet with an initial upward velocity of 21 ft/s. The ball height h (in feet) after
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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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