B-r-3
Substitute values
9-2-3
9-2=7
7-3=4
Final answer: 4
-7.5 is the answer to the question you were looking for
The first one states that there are 6 cups of orange juice for every _ cups of punch
There are 6 cups of orange juice and 4 cups of cranberry in 10 cups of juice because 6 c orange + 4 c cranberry = 10 cups total punch
So for 6 cups of orange juice there would be 10 cups of punch.
The 3rd one states that the ratio of cranberry juice to punch is _:_
Punch is cranberry and orange combined- at the ratio of 4:6
So for 4 cups of cranberry, there would be 10 cups punch (4 c cranberry + 6 c orange = 10 c punch)
So the ratio would be 4:10, it can be simplified like fractions as 2:5
I don't know is you have to but if you do, don't forget to simplify the ratios.
Good luck!
Answer:
+
*LN(|
|) +C
Step-by-step explanation:
we will have to do a trig sub for this
use x=a*tanθ for sqrt(x^2 +a^2) where a=2
x=2tanθ, dx= 2 sec^2 (θ) dθ
this turns 
into integral(sqrt( [2tanθ]^2 +4) * 2sec^2 (θ) )dθ
the sqrt( [2tanθ]^2 +4) will condense into 2sec^2 (θ) after converting tan^2(θ) into sec^2(θ) -1
then it simplifies into integral(4*sec^3 (θ)) dθ
you will need to do integration by parts to work out the integral of sec^3(θ) but it will turn into (1/2)sec(θ)tan(θ) + (1/2) LN(|sec(θ)+tan(θ)|) +C
then you will need to rework your functions of θ back into functions of x
tanθ will resolve back into 
(see substitutions) while secθ will resolve into 
sec(θ)= is from its ratio identity of hyp/adj where the hyp. is 
and adj is 2 (see tan(θ) ratio)
after resolving back into functions of x, substitute ratios for trig functions:
= + *LN(||) +C
