Answer:
Should be 0.6106 though i could be wrong
Explanation:
0.150 M AgNO3 = x mol / 0.200 Liters
x mol = 0.03 mol AgNO3
0.03 mol AgNO3 (169.9g AgNO3 / 1 mol AgNO3) We are converting moles to grams here with stoichiometry.
Final answer = 5.097 grams, but if you want it in terms of sig figs then it is 5.09 grams.
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Ideal behavior is approached by gases when the conditions of the system are at a low pressure and high temperatures. Therefore, the correct answer is C. At the conditions of lowest temperature highest pressure, gases will deviate from an ideal gas.
