Answer:
B- Sodium loses an electron.
D- Fluorine gains an electron.
Sodium is oxidized.
Explanation:
The reaction equation is given as:
Na + F → NaF
In this reaction, Na is the reducing agent. It loses an electron and then becomes oxidized. By so doing, Na becomes isoelectronic with Neon.
Fluorine gains the electron and then becomes reduced. This makes fluorine also isoelectronic with Neon.
This separation of charges on the two species leads to an electrostatic attraction which forms the ionic bonds.
Answer:
Q3. A bridge is built without expansion gaps.
Explain what could happen to the bridge if the temperature became:
a) much hotter than the day it was built.
b) much colder than the day it was built.
P.s. (this is not a select option question, explain each according to the question)
Answer:
Greatly affect.
Explanation:
This level of fishing will greatly affect the populations of the other fish in the simulated reef because overfishing disturbs the equilibrium in the marine ecosystem. One fish is a food of another fish or the big fish act as a controller which controls the population of other small fishes and in that way the ecosystem is present in equilibrium state so overfishing will greatly affect the marine ecosystem.
Structures of <span>
1-bromo-3-methyl-2-butene and </span>
2-bromo-3-methyl-2-butene are shown below.
It can be seen that <span>
1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in
2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore,
1-bromo-3-methyl-2-butene will show this peak and
2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.