Answer:
7.56 x 10^13 J/mol
Explanation:
Binding energy = (Mass defect) × (velocity of light)² = (84 × 10^-5) × (3 × 10^8)^2 = 756 × 10^11 J = 7.56 × 10^13 J/mol
Hope this helps -Paige
Answer:
CH
Explanation:
The empirical formular is the simplest formular of a compound. It shows the relative number of elements present in a compounds. It shows the number of atoms of elements present in simple ratios.
In both compounds, the ratio of the carbon to hydrogen s 1:1
In C2H2;
C : H = 2 : 2 (Which is equivalent to 1 : 1)
In C6H6;
C : H = 6 : 6 (Which is equivalent to 1 : 1)
This means the empirical formular is CH
Answer:
0.0102 L or 10.2 mL
Explanation:
From the question given above, the following data were obtained:
Molarity = 0.250 M
Mole = 0.00255 mole
Volume =?
Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:
Molarity = mole / Volume
With the above formula, we can obtain the volume as follow:
Molarity = 0.250 M
Mole = 0.00255 mole
Volume =?
Molarity = mole / Volume
0.250 = 0.00255 / volume
Cross multiply
0.250 × volume = 0.00255
Divide both side by 0.250
Volume = 0.00255 / 0.250
Volume = 0.0102 L
Covert 0.0102 L to mL.
1 L = 1000 mL
Therefore,
0.0102 L = 0.0102 L × 1000 / 1 L
0.0102 L = 10.2 mL
Thus, the volume is 0.0102 L or 10.2 mL
Orbital diagram:
<h3>Explanation</h3>
Fluorine F is found in the second column from the right end of a modern periodic table. Fluorine is next to and on the left of the noble gas element neon. A neutral fluorine atom is one electron short of neon, which contains 8 electrons in the outermost shell when neutral. As a result, there are 7 electrons in the outermost shell of a fluorine atom.
Fluorine is in period 2. Its electrons occupy two main shells. The second main shell is the outermost shell of F. There are two subshells in the second main shell:
- 2s, which holds up to two electrons, and
- 2p, which holds up to six electrons.
A 2s electron carries less energy than a 2p electron. By Aufbau principle, the seven electrons will fill the two spaces in 2s before moving on the 2p. Among the 7 outermost shell electrons, 
will end up going to 2p.
The only 2s orbital is filled with two electrons. The two 2s electrons will pair up with opposite spins, as seen with the two arrows. Two of the 2p orbitals will contain two electrons. Those electrons will also pair up. The third 2p orbital will contain only one electron. That electron can spin either 
or 
. Here that electron is shown as an upward arrow.
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