The number of C2H5OH in a 3 m solution that contain 4.00kg H2O is calculate as below
M = moles of the solute/Kg of water
that is 3M = moles of solute/ 4 Kg
multiply both side by 4
moles of the solute is therefore = 12 moles
by use of Avogadro law constant
1 mole =6.02 x10^23 molecules
what about 12 moles
=12 moles/1 moles x 6.02 x10^23 = 7.224 x10^24 molecules
Answer: 0.100 m 
Explanation:
Elevation in boiling point is given by:
= Elevation in boiling point
i= vant hoff factor
= boiling point constant
m= molality
1. For 0.100 m 
, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be 
2. For 0.100 m 
, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be 
3. For 0.200 m 
, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be 
4. For 0.060 m 
, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be 
Thus as concentration of solute is highest for , the elevation in boiling point is highest and thus has the highest boiling point.
Answer:
law of independent assortment
The correct answer is A: Vapor pressure lowering.
Certain properties in chemistry are called colligative properties. These colligative properties depends on the amount of solute present.
Examples of colligative properties include;
- Vapor pressure lowering
- Freezing point depression
- Boiling point elevation
- Osmotic pressure
When a solute is introduced into water, the vapour pressure of water is lowered.
Hence, when KI is added to a sample of water, vapor pressure lowering occurs.
brainly.com/question/10323760
I hope my calculation is correct :P
