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lilavasa [31]
3 years ago
5

Which graph represents the solution set for -4(1-x)<_-12 +2

Mathematics
1 answer:
Alja [10]3 years ago
8 0

Answer:

-4(1-x) 《 -12 +2

-4 + 4x 《 -12 + 2

4x 《 -10 + 4

4x 《 -6

x 《 -1.5

It's the region towards left of the vertical line x = -1.5

The line should be bold because it's included

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Romashka [77]

First, let's convert each line to slope-intercept form to better see the slopes.

Isolate the y variable for each equation.

2x + 6y = -12

Subtract 2x from both sides.

6y = -12 - 2x

Divide both sides by 6.

y = -2 - 1/3x

Rearrange.

y = -1/3x - 2


Line b:

2y = 3x - 10

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y = 1.5x - 5


Line c:

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Add 2y to both sides.

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Add 4 to both sides.

2y = 3x + 4

Divide both sides by 2.

y = 1.5x + 2


Now, let's compare our new equations:

Line a: y = -1/3x - 2

Line b: y = 1.5x - 5

Line c: y = 1.5x + 2

Now, the rule for parallel and perpendicular lines is as follows:

For two lines to be parallel, they must have equal slopes.

For two lines to be perpendicular, one must have the negative reciprocal of the other.

In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.

However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.

<h3><u>B and C are parallel, no perpendicular lines.</u></h3>
8 0
3 years ago
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