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Kryger [21]
3 years ago
15

A plane left Atlanta at 4:50 and arrived at Boston in 3 hours and 15 minutes. When did it arrive in Boston?

Mathematics
1 answer:
sashaice [31]3 years ago
4 0

Answer: 8:05 pm

Step-by-step explanation: 4 hours + 3 hours = 7 hours

50 min + 15 min = 1 hour, 5 min

add those together

watch out for time zones when crossing

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Y=3(x-2)+1 how can i graph this into slope intercept form
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y=3x-5

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Nicholas has 8 pieces of rope that are 4 yards each. He uses 4 pieces that are each 4 feet long.
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(Who ever Answers the question for this lil guy&gt; ʕ •ᴥ•ʔ, Gets brainliest!!)
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Step-by-step explanation:

8 0
3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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