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deff fn [24]
3 years ago
9

Angle A and angle C are the right angles.

Mathematics
1 answer:
goblinko [34]3 years ago
3 0
I think u forgot the picture?
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Write as<br> logarithm with base 4:<br> 4<br> -5<br> 2<br> -4
NeX [460]

Answer:

log_4(256)=4

log_4(1/1024)=-5

log_4(16)=2

log_4(1/256)=-4

Step-by-step explanation:

We want to write a number, x, such that

Log_4(y)=x.

In exponential form that is 4^x=y.

So first number is x=4.

4^4=256 which means log_4(256) is 4 as a logarithm with base 4.

The second number is x=-5.

4^-5=1/4^5=1/1024 which means log_4(1/1024) is -5 as a logarithm with base 4.

The third number is x=2.

4^2=16 so log_4(16) is 2 as a logarithm with base 4.

The fourth number is x=-4.

Since 4^4=256 then 4^-4=1/256 which means -4 as a logarithm with base 4 is log_4(1/256).

8 0
3 years ago
vivi is a drummer for a band. she burns 756 calories while drumming for 3 hours. she burns the same number of calories each hour
Airida [17]

Answer:

252 cph

Step-by-step explanation:

756 divide by 3 is 252

6 0
3 years ago
Shelly is tying to improve her running time for track race. She ran the first race 43.13 seconds. Her time was 43.1 seconds in t
grandymaker [24]

Answer:

42.77

Step-by-step explanation:

The pattern is taking away 0.3. 43.07 minus 0.3 equals 42.77

3 0
3 years ago
Use the Pythagorean Theorem to find the distance to the nearest tenth, between F(9, 5) and G(-2, 2). (Hint: Place F and G on the
artcher [175]
Put a point H on (9, 2).  Sketch a triangle out of the three points.  Distance between (-2, 2) and (9, 2) is going to be 11.  Distance between (9, 2) and (9, 5) is going to be 3.    These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>
6 0
3 years ago
A projectile is thrown upward off a 130ft cliff at a velocity of 15ft/second. How long before it reaches a height of 25ft?
zhuklara [117]

Answer:

The time taken for the projectile to reach the given height is 1.2 s.

Step-by-step explanation:

Given;

height of travel, h = 25 ft

initial velocity of the projectile, u = 15 ft/s

The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;

h = ut + ¹/₂gt²

25 = 15t + ¹/₂(9.8)t²

25 = 15t + 4.9t²

4.9t² + 15t - 25 = 0

solving the quadratic equation, we will have the following solution of t;

t = 1.2 s

Therefore, the time taken for the projectile to reach the given height is 1.2 s.

5 0
3 years ago
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